Consider the running totals as each player joins: P 3 Total weight: 3 Not winning P 3, P 2 Total weight: 3 + 4 = 7 Not winning P 3, P 2, P 4 Total weight: 3 + 4 + 2 = 9 Winning R 2, P 3, P 4, P 1 Total weight: 3 + 4 + 2 + 6 = 15 Winning We will list all the sequential coalitions and identify the pivotal player. Translated into a weighted voting system, assuming a simple majority is needed for a proposal to pass: Listing the winning coalitions and marking critical players: \(\begin{array} {lll} {\{\underline{\mathrm{H} 1}, \underline{\mathrm{H} 2}\}} & {\{\underline{\mathrm{H} 1}, \underline{\mathrm{OB}}, \mathrm{NH}\}} & {\{\underline{\mathrm{H} 2}, \underline{\mathrm{OB}}, \mathrm{NH}, \mathrm{LB}\}} \\{\{\underline{\mathrm{H} 1}, \underline{\mathrm{OB}}\}} & {\{\underline{\mathrm{H} 1}, \underline{\mathrm{OB}}, \mathrm{LB}\}} & {\{\underline{\mathrm{H} 2}, \underline{\mathrm{OB}}, \mathrm{NH}, \mathrm{GC}}\} \\{\{\underline{\mathrm{H} 2}, \underline{\mathrm{OB}}\}} & {\{\underline{\mathrm{H} 1}, \underline{\mathrm{OB}}, \mathrm{GC}\}} & {\{\underline{\mathrm{H} 2}, \underline{\mathrm{OB}}, \mathrm{LB}, \mathrm{GC}}\} \\{\{\underline{\mathrm{H} 1}, \underline{\mathrm{H} 2}, \mathrm{NH}\}} & {\{\underline{\mathrm{H} 1}, \underline{\mathrm{OB}}, \mathrm{NH}, \mathrm{LB}\}} & {\{\underline{\mathrm{H} 2}, \underline{\mathrm{OB}}, \mathrm{NH}, \mathrm{LB}, \mathrm{GC}\}} \\{\{\underline{\mathrm{H} 1}, \underline{\mathrm{H} 2}, \mathrm{LB}\}} & {\{\underline{\mathrm{H} 1}, \mathrm{OB}, \mathrm{NH}, \mathrm{GC}\}} & {\{\mathrm{H} 1, \mathrm{H} 2, \mathrm{OB}\}} \\{\{\underline{\mathrm{H} 1}, \underline{\mathrm{H} 2}, \mathrm{GC}\}} & {\{\underline{\mathrm{H} 1}, \underline{\mathrm{OB}}, \mathrm{LB}, \mathrm{GC}\}} & {\{\mathrm{H} 1, \mathrm{H} 2, \mathrm{OB}, \mathrm{NH}\}} \\{\{\underline{\mathrm{H} 1}, \underline{\mathrm{H} 2}, \mathrm{NH}, \mathrm{LB}\}} & {\{\underline{\mathrm{H} 1}, \underline{\mathrm{OB}}, \mathrm{NH}, \mathrm{LB} . (a) 13!, (b) 18!, (c) 25!, (d) Suppose that you have a supercomputer that can list one trillion ( $$ 10^{12} $$ ) sequential coalitions per second. \left\{P_{1}, P_{2}, P_{3}, P_{4}, P_{5}\right\} stream 3 0 obj << We will have 3! The quota is 8 in this example. If there are 7 candidates, what is the smallest number of votes that a plurality candidate could have? Consider the weighted voting system [17: 13, 9, 5, 2]. Notice that in this system, player 1 can reach quota without the support of any other player. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. /Length 786 endobj \hline P_{5} \text { (Scottish Green Party) } & 3 & 3 / 27=11.1 \% \\ 12? /Parent 20 0 R \hline P_{2} & 1 & 1 / 6=16.7 \% \\ 1 0 obj << There are four candidates (labeled A, B, C, and D for convenience). /Length 1368 Sample Size Calculator | 30 0 obj << Does not meet quota. endobj Find a weighted voting system to represent this situation. The number of salespeople assigned to work during a shift is apportioned based on the average number of customers during that shift. Treating the percentages of ownership as the votes, the system looks like: \([58: 30,25,22,14,9]\). \hline \text { Hempstead #2 } & 31 \\ How about when there are four players? /MediaBox [0 0 362.835 272.126] They are trying to decide whether to open a new location. \hline P_{1} & 4 & 4 / 6=66.7 \% \\ A player who has no power is called a dummy. Apportion those coins to the investors. \(\begin{array}{ll} We now need to consider the order in which players join the coalition. The first thing to do is list all of the sequential coalitions, and then determine the pivotal player in each sequential coalition. We also acknowledge previous National Science Foundation support under grant numbers 1246120, 1525057, and 1413739. /Rect [188.925 2.086 190.918 4.078] A weighted voting system will often be represented in a shorthand form:\[\left[q: w_{1}, w_{2}, w_{3}, \ldots, w_{n}\right] \nonumber \]. Conversion rates in this range will not be distinguishable from the baseline (one-sided test). There are some types of elections where the voters do not all have the same amount of power. Consider a weighted voting system with three players. Four options have been proposed. /Annots [ 22 0 R ] In the weighted voting system \([17: 12,7,3]\), determine which player(s) are critical player(s). A small country consists of three states, whose populations are listed below. \hline \text { Glen Cove } & 2 \\ The sequential coalition shows the order in which players joined the coalition. Explore and describe the similarities, differences, and interplay between weighted voting, fair division (if youve studied it yet), and apportionment. The sequential coalition is used only to figure out the power each player possess. This happens often in the business world where the power that a voter possesses may be based on how many shares of stock he/she owns. Notice that player three is a dummy using both indices. What are the similarities and differences compared to how the United States apportions congress? Under Shapley-Shubik, we count only coalitions of size N. One ordinary coalition of 3 players, {P 1,P 2,P 3}, has 6 sequential coalitions: hP 1,P 2,P 3i, hP 1,P 3,P 2i, hP 2,P 1,P 3i, hP 3,P 2,P 1i, hP 2,P 3,P 1i, hP 3,P 1,P 2i. @f9rIx83{('l{/'Y^}n _zfCVv:0TiZ%^BRN]$")ufGf[i9fg @A{ E2bFsP-DO{w"".+?8zBA+j;jZH5)|FdEJw:J!e@DjbO,0Gp Half of 15 is 7.5, so the quota must be . The quota is 16 in this example. Weighted voting is applicable in corporate settings, as well as decision making in parliamentary governments and voting in the United Nations Security Council. Sometimes in a voting scenario it is desirable to rank the candidates, either to establish preference order between a set of choices, or because the election requires multiple winners. That also means that any player can stop a motion from passing. next to your five on the home screen. Send us an e-mail. Additionally, they get 2 votes that are awarded to the majority winner in the state. A coalition is any group of players voting the same way. Each state has a certain number of Electoral College votes, which is determined by the number of Senators and number of Representatives in Congress. How could it affect the outcome of the election? Next we determine which players are critical in each winning coalition. Thus, player four is a dummy. \left\{\underline{P}_{1}, \underline{P}_{2}, P_{3}\right\} & \left\{\underline{P}_{1}, \underline{P}_{2}, P_{4}\right\} \\ \left\{\underline{P}_{1}, \underline{P}_{2}, P_{5}\right\} & \left\{\underline{P}_{1}, \underline{P}_{3}, \underline{P}_{4}\right\} \\ \left\{\underline{P}_{1}, \underline{P}_{3}, \underline{P}_{5}\right\} & \left\{\underline{P}_1, \underline{P}_{4}, \underline{P}_{5}\right\} \\ \left\{\underline{P}_{2}, \underline{P}_{3}, \underline{P}_{4}\right\} & \left\{\underline{P}_{2}, \underline{P}_{3}, \underline{P}_{5}\right\}\\ \left\{P_{1}, P_{2}, P_{3}, P_{4}\right\} & \left\{P_{1}, P_{2}, P_{3}, P_{5}\right\} \\ \left\{\underline{P}_{1}, P_{2}, P_{4}, P_{5}\right\} & \left\{\underline{P}_{1}, P_{3}, P_{4}, P_{5}\right\} \\ \left\{\underline{P}_{2}, \underline{P}_{3}, P_{4}, P_{5}\right\} & \\ \left\{P_{1}, P_{2}, P_{3}, P_{4}, P_{5}\right\} & \end{array}\), \(\begin{array}{|l|l|l|} Accessibility StatementFor more information contact us atinfo@libretexts.orgor check out our status page at https://status.libretexts.org. /Filter /FlateDecode Which apportionment paradox does this illustrate? Can we come up with a mathematical formula for the number of sequential coalitions? endobj xO0+&mC4Bvh;IIJm!5wfdDtV,9"p 30 0 obj << This means player 5 is a dummy, as we noted earlier. The marketing committee at a company decides to vote on a new company logo. \hline \text { North Hempstead } & 0 & 0 / 48=0 \% \\ In order for only one decision to reach quota at a time, the quota must be at least half the total number of votes. Let SS i = number of sequential coalitions where P i is pivotal. If there is such a player or players, they are known as the critical player(s) in that coalition. \hline \text { Glen Cove } & 0 & 0 / 48=0 \% \\ The total weight is . {P2, P3} Total weight: 5. As Im sure you can imagine, there are billions of possible winning coalitions, so the power index for the Electoral College has to be computed by a computer using approximation techniques. /Resources 23 0 R a group of voters where order matters. \end{array}\). endobj Find the winner under the Borda Count Method. Player three joining doesnt change the coalitions winning status so it is irrelevant. /Filter /FlateDecode Research the history behind the Electoral College to explore why the system was introduced instead of using a popular vote. Note, that in reality when coalitions are formed for passing a motion, not all players will join the coalition. Consider the voting system \([q: 3, 2, 1]\). \(\left\{P_{2}, P_{3}\right\}\) Total weight: 5. In the system, player one has a weight of 10. In the weighted voting system \([17: 12,7,3]\), determine the Shapely-Shubik power index for each player. The value of the Electoral College (see previous problem for an overview) in modern elections is often debated. For a proposal to pass, four of the members must support it, including at least one member of the union. In particular, if a proposal is introduced, the player that joins the coalition and allows it to reach quota might be considered the most essential. /Border[0 0 0]/H/N/C[.5 .5 .5] We start by listing all winning coalitions. There are two different methods. Most calculators have a factorial button. The total weight is . Notice that player 5 has a power index of 0, indicating that there is no coalition in which they would be critical power and could influence the outcome. \left\{\underline{P}_{1}, \underline{P}_{2}\right\} \\ \(< P_{1}, \underline{P}_{2}, P_{3} > \quad < P_{1}, \underline{P}_{3}, P_{2} > \quad< P_{2}, \underline{P}_{1_{2}} P_{3} >\), \(
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